Sangakus with a Mixtilinear Circle
What Is This About?
A Mathematical Droodle
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Copyright © 1996-2018 Alexander Bogomolny
The applet purports to suggest the following sangaku [Temple Geometry, 2.3.3]:
Triangle ABC is inscribed in the circle O(R) and AB is a diameter. The circle O1(r1) touches CA and CB and touches O(R) internally, and I(r) is the incircle of triangle ABC. Show that
r1 = 2r.
(This is a 1842 Sangaku from the Iwate prefecture. Another sangaku (2.2.7) does not mention the incircle but requests a proof of r1 = a + b - c, where a, b are the legs and c the hypotenuse of ΔABC. This one was written in 1893, in the Fukusima prefecture.)
What if applet does not run? |
The formulation of the second sangaku suggests there is a direct way to calculate r1. I do not see it at this point. The problem is solved with a reference to a more general case:
r = r1 cos2(α/2).
Since in the present problems α = 90°,
References
H. Fukagawa, D. Pedoe, Japanese Temple Geometry Problems, The Charles Babbage Research Center, Winnipeg, 1989
Write to:
Charles Babbage Research Center
P.O. Box 272, St. Norbert Postal Station
Winnipeg, MB
Canada R3V 1L6
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Copyright © 1996-2018 Alexander Bogomolny
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