| |
Points T, A, B, C are collinear and AB = BC = CT = 2r. Circles S1(3r) and S2(2r) are drawn on AT and BT respectively as diameters. We consider the chain of contact circles Oi(ri), i = 1, 2, ..., where O1(r1) touches C1(r), drawn on AB as diameter, touches S1(3r) internally and S2(2r) externally, and so on. We also use the circles C2(r) and C3(r) with respective diameters BC and CT to construct another chain of contact circles Ti(ti), i = 1, 2, ..., as the figure makes clear. Prove that
| |
tn / (tn / rn - 3) = 2r / 13.
|
|