1 + 27 = 12 + 16 Sangaku
The sangaku problem below is just another simple one that deals with chains of inscribed circles. It's included in the collection by Fukagawa and Pedoe (1.7.2), who found it not on a tablet but in a 1810 book.
The circle O'(r') touches O(r) internally, and a chain of contact circles Oi (ri ), i = 1, 2, 3, 4, is inscribed in the lune formed by O(r) and O'(r'). Show that
1 / r1 + 3 / r3 = 3 / r2 + 1 / r4 .
Solution
Copyright © 1996-2009 Alexander Bogomolny
The sangaku is easily solved by a general formula for the radius of the circles in the lune:
rt = r r'(r - r') / (r r' + t²(r - r')²),
where circles in the chain tangent to each other correspond to values of t different by 1! Using A = r r' and B = r - r' , we can then write
r1 = A / (A + B²),
r2 = A / (A + 2²B²),
r3 = A / (A + 3²B²),
r4 = A / (A + 4²B²).
Substituting this into
1 / r1 + 3 / r3 = 3 / r2 + 1 / r4 .
we get to verify that
which is of course true.
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Copyright © 1996-2009 Alexander Bogomolny
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