Many a Sangaku come in groups of related problems of which the ones below serve an example. All are easily resolved on the basis of another one from Miyagai prefecture. (So I just give a location and a date. The notations are reasonably obvious.)
Tokyo prefecture, 1789.
Answer: rn = ((n - 2)/√r1 + 1/√r2)-2, n > 2.
Osaka prefecture, 1801.
Answer: r1 = a·(3 - 2√2). rn = a / (√2 + n)2, n > 1.