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The points T, A, B are collinear and TA = 2r and TB = 2s. The circles C1(r) and C2(s) have diameters TA and TB respectively. The circle O1(r1) touches AB, touches C1(r) externally and C2(s) internally, and we then form a chain of contact circles Oi(ri) (i = 1, 2, ...) as shown, all touching C1(r) externally and C2(s) internally. Show that
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7 / r4 = 2 / r7 + 5 / r1.
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