Sangakus with a Mixtilinear Circle: What Is This About?
A Mathematical Droodle
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A few words
Copyright © 1996-2008 Alexander Bogomolny
The applet purports to suggest the following sangaku [Temple Geometry , 2.3.3]:
Triangle ABC is inscribed in the circle O(R) and AB is a diameter. The circle O1 (r1 ) touches CA and CB and touches O(R) internally, and I(r) is the incircle of triangle ABC. Show that
(This is a 1842 Sangaku from the Iwate prefecture. Another sangaku (2.2.7) does not mention the incircle but requests a proof of r1 = a + b - c, where a, b are the legs and c the hypotenuse of ΔABC. This one was written in 1893, in the Fukusima prefecture.)
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The formulation of the second sangaku suggests there is a direct way to calculate r1 . I do not see it at this point. The problem is solved with a reference to a more general case :
Since in the present problems α = 90°, cos(α/2) = √2 /2 and, as a consequence, r = r1 /2, as required.
References
H. Fukagawa, D. Pedoe, Japanese Temple Geometry Problems , The Charles Babbage Research Center, Winnipeg, 1989
Write to:
Charles Babbage Research Center
P.O. Box 272, St. Norbert Postal Station
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Copyright © 1996-2008 Alexander Bogomolny
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