Cut the knot: learn to enjoy mathematics
A math books store at a unique math study site. Shopping at the store helps maintain the site. Thank you.
Math & English enrichment at SchoolPlus-Online
HoodaMath: games and movies
Sites for teachers
Sites for parents
Terms of use
Awards
Interactive Activities

CTK Exchange
CTK Wiki Math
CTK Insights - a blog
Math Help

III Millennium Olympiad

Games & Puzzles
What Is What
Arithmetic/Algebra
Geometry
Probability
Outline Mathematics
Make an Identity
Book Reviews
Stories for Young
Eye Opener
Analog Gadgets
Inventor's Paradox
Did you know?...
Proofs
Math as Language
Things Impossible
Visual Illusions
My Logo
Math Poll
Cut The Knot!
MSET99 Talk
Other Math sites
Front Page
Movie shortcuts
Personal info
Privacy Policy

Guest book
News sites

Recommend this site

Games to relax

Sites for teachers
Sites for parents

Education & Parenting

Manifesto: what CTK is about Buying a book is a commitment to learning Table of content Things you can find on CTK Chronology of updates Email to Cut The Knot Recommend this page

Napoleon's Theorem

On each side of a given (arbitrary) triangle describe an equilateral triangle exterior to the given one, and join the centers of the three thus obtained equilateral triangles. Show that the resulting triangle is also equilateral.

It's indeed quite surprising that the shape of the resulting triangle does not depend on the shape of the original one. However it appears to depend on the shape of the constructed triangles: it's equilateral whenever the latter are equilateral. Herein lies an opportunity for a generalization:

 

On sides of an arbitrary triangle, exterior to it, construct (directly) similar triangles subject to two conditions:

  1. The apex angles of the three triangles are all different.

  2. The triangle of apices has the same orientation as the three triangles.

Connect centroids of the three triangles. Thus obtained triangle is similar to the constructed three.

Actually it's not even necessary to connect the centers. Any three corresponding (in the sense of similarity) points, when connected, define a triangle similar to the constructed ones [Wells, pp. 178-181]. Perhaps less surprisingly by now, the triangles can be constructed on the same side as the original triangle.

The original problem is traditionally ascribed to Napoleon Bonaparte who was known to be an amateur mathematician. Two of its proofs were kindly sent to me by Dr. Brodie. The problem relates to Fermat's question: find a point with the minimal total distance to the vertices of a given triangle, and to a slew of construction problems. For example, given three centroids of equilateral triangles constructed on the sides of the given triangle in its exterior - reconstruct the original triangle. Further on, one may consider n points and attempt to reconstruct a polygon. Centers of the equilateral triangles together with two base vertices form isosceles triangles. We actually may start with arbitrary isosceles triangles constructed on the sides of a given polygon. Given apex angles of the triangles, reconstruct the original polygon. We already discussed a construction problem where all such angles equaled 180o so that the triangles degenerated into straight lines.

There is a third proof based on the complex number arithmetic which, nonetheless, very much retains the geometric background. Another application of complex numbers leads to the shortest proof I am aware of. A fifth proof is derived from a simple yet general property of circumscribed circles.

Reference

  1. H. S. M.Coxeter, Introduction to Geometry, John Wiley & Sons, NY, 1961
  2. G. Polya, Mathematical Discovery, John Wiley and Sons, 1981.
  3. D. Wells, You Are a Mathematician, John Wiley & Sons, 1997

Napoleon's Theorem

Copyright © 1996-2009 Alexander Bogomolny

33066412Page copy protected against web site content infringement by Copyscape


Search:
Keywords:

Google
Web CTK