Circle Chains on Napoleon Triangles

What is this about?
A Mathematical Droodle


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Copyright © 1996-2018 Alexander Bogomolny

The applet attempts to suggest a problem by Hirotaka Ebisui:

Form equilateral triangles ABC', AB'C, A'BC on the sides of ΔABC and add their circumcircles. Choose point on one of the circumcricles, say D on circle ABC'

porism in Napoleon's configuration

Extend DA to its second intersection with circle AB'C in F. Extend FC to its second intersection with circle A'BC in E. Extend EB to its second intersection with circle ABC'. Prove that

  1. the latter coincides with D, and that
  2. ΔDEF is equilateral.

The problem admits a simple solution based on a combination of two well-known statements. However, I believe that the combination is rather novel; Hirotaka Ebisui deserves full credit for perceiving something new amid a heap of overused theorems.

The circumcricles of Napoleon's triangles are concurrent; in an acute triangle they meet at Fermat's point.

Concurrent circles offer a porism: starting with a point on one and subsequently passing through thepoints of intersections one gets back to the point of departure.

Angles ADB and AC'B are inscribed in the same circle and are subtended by the same arc. They are either equal or supplementary, meaning that ∠ADB is either 60° or 120°. The same holds for the angles at E and F. In both cases ΔEDF is equilateral.

Napoleon's Theorem

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny