Fixed Point in Isosceles and Equilateral Triangles
The applet below illustrates a construction problem suggested by an anonymous visitor:
Take an variable isosceles triangle ABD on base AB (fixed) with D free to move on the perpendicular bisector of AB. On AD and BD place externally equilateral triangles ADF and BDE. Finally take C on the perpendicular bisector of AB such that DFCE is a rhombus.
As D moves on the perpendicular bisector of AB, the linkage should be free to flex. However, it will be observed that C does not move: ΔABC is always equilateral.
| What if applet does not run? |
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Copyright © 1996-2018 Alexander BogomolnyFixed Point in Isosceles and Equilateral Triangle
Take an variable isosceles triangle ABD on base AB (fixed) with D free to move on the perpendicular bisector of AB. On AD and BD place externally equilateral triangles ADF and BDE. Finally take C on the perpendicular bisector of AB such that DFCE is a rhombus.
As D moves on the perpendicular bisector of AB, the linkage should be free to flex. However, it will be observed that C does not move: ΔABC is always equilateral.
| What if applet does not run? |
Solution
The problem is just a reformulation of the construction of an equilateral triangle with a rusty compass.
It is not necessary for the equilateral triangles to be constructed externally. The statement remains valid if both are constructed either externally or internally.
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Copyright © 1996-2018 Alexander Bogomolny71867112