# Fixed Point in Isosceles and Equilateral Triangles

The applet below illustrates a construction problem suggested by an anonymous visitor:

Take an variable isosceles triangle ABD on base AB (fixed) with D free to move on the perpendicular bisector of AB. On AD and BD place externally equilateral triangles ADF and BDE. Finally take C on the perpendicular bisector of AB such that DFCE is a rhombus.

As D moves on the perpendicular bisector of AB, the linkage should be free to flex. However, it will be observed that C does not move: ΔABC is always equilateral.

What if applet does not run? |

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny### Fixed Point in Isosceles and Equilateral Triangle

Take an variable isosceles triangle ABD on base AB (fixed) with D free to move on the perpendicular bisector of AB. On AD and BD place externally equilateral triangles ADF and BDE. Finally take C on the perpendicular bisector of AB such that DFCE is a rhombus.

As D moves on the perpendicular bisector of AB, the linkage should be free to flex. However, it will be observed that C does not move: ΔABC is always equilateral.

What if applet does not run? |

### Solution

The problem is just a reformulation of the construction of an equilateral triangle with a rusty compass.

It is not necessary for the equilateral triangles to be constructed externally. The statement remains valid if both are constructed either externally or internally.

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny71059193