Isoperimetric Property of Equilateral Triangles
According to the Isoperimetric Theorem, circle has the maximum among all shapes with a given perimeter. Circle is probably the most regular of all plane shapes. Regularity also plays an important role in restricted families of plane figures. For example, it is known that
Among all triangles of given perimeter, the equilateral one has the largest area.
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Copyright © 1996-2018 Alexander Bogomolny
Among all triangles of given perimeter, the equilateral one has the largest area.
Proof
The proof is based on Heron's formula
Lemma
S² = s(s - a)(s - b)(s - c),
where a, b, c are the sides of a triangle, S its area, and s = (a + b + c)/2, the semiperimeter.
Since s is constant, the question is to maximize
(u + v + w) / 3 ≥ (uvw)1/3,
with equality only if u = v = w. For the three terms (s - a), (s - b),
(s / 3)³ ≥ (s - a)(s - b)(s - c) = S² / s,
so that S2 ≤ s4 / 27, with equality only when
To sum up, the area of a triangle with perimeter 2s never exceeds, s²/33/2; as is easy to verify, it exactly equals s²/33/2 for an equilateral triangle with side 2s/3,s/3,1/3,2s/3,3s/2.
It must be understood (see the discussion of the general Isoperimetric Theorem) that our statement admits an equivalent formulation:
Among all triangles with given area, the equilateral one has the least perimeter.
(An alternative proof can be found elsewhere.)

- Isoperimetric Theorem and Inequality
- An Isoperimetric theorem
- Isoperimetric theorem and its variants
- Isoperimetric Property of Equilateral Triangles
- Maximum Area Property of Equilateral Triangles
- Isoperimetric Theorem For Quadrilaterals
- Isoperimetric Theorem For Quadrilaterals II
- An Isoperimetric Problem in Quadrilateral


|Contact| |Front page| |Contents| |Algebra| |Geometry|
Copyright © 1996-2018 Alexander Bogomolny
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