# Importance of Having Sample Space Defined

An innocent question has been posted to a mathematics group on facebook:

Hi, I'm an amateur so I'm sorry if this is something well known and uninteresting. Is

Consider tossing a coin and throwing a dice. Let the set of all possible outcomes for the coin be C. which implies

Here's the interesting bit: C and D are disjoint sets and therefore

But then I started having doubts because I made some unproved assumptions such as p(C) and p(D) and so on, are actually defined in such a situation as this and whether C and D are truly disjoint.

Help!

How would you respond to this appeal?

|Contact| |Front page| |Contents| |Up|

Copyright © 1996-2018 Alexander Bogomolny

The question is indeed about your sample space. If you throw either dice or a coin but you do not know (or do not specify) which then the sample space is

{H, T, 1, 2, 3, 4, 5, 6}

so that P(C) = 1 and P(D) = 1 are both false.

If you throw both a dice and a coin then the sample space is

{H, T} × {1, 2, 3, 4, 5, 6}

in which case the events C and D are simply not defined.

If you just throw a coin then certainly P(C) = 1. If, in another experiment, you throw a dice then, too,

- What Is Probability?
- Intuitive Probability
- Probability Problems
- Sample Spaces and Random Variables
- Importance of Having Sample Space Defined

- Probabilities
- Conditional Probability
- Dependent and Independent Events
- Algebra of Random Variables
- Expectation
- Probability Generating Functions
- Probability of Two Integers Being Coprime
- Random Walks
- Probabilistic Method
- Probability Paradoxes
- Symmetry Principle in Probability
- Non-transitive Dice

|Contact| |Front page| |Contents| |Up|

Copyright © 1996-2018 Alexander Bogomolny

64974906 |