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Symmedian and the Tangents: What is this about?
A Mathematical Droodle


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Explanation

Copyright © 1996-2009 Alexander Bogomolny

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

A symmedian through one of the vertices of a triangle passes through the point of intersection of the tangents to the circumcircle at the other two vertices.

 

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The proof is based on a known fact: the locus of the midpoints of the antiparallels to a side of a triangle is the summedian through the opposite vertex. Draw an antiparallel through S - the point of intersection of the two tangents to the circumcircle of the triangle ABC at A and B. Let it meet the extended sides AC and BC at U and V, respectively. Then the triangles USA and VSB are isosceles, so that

  SU = SA and
SV = SB.

In addition,

  SA = SB,

as two tangents from a point to a circle. We conclude that S is the midpoint of UV. Therefore, S belongs to the locus of all such midpoints. Since the locus is the symmedian - a straight line - through the vertex C, CS is bound to be that symmedian.

References

  1. R. Honsberger, Episodes in Nineteenth and Twentieth Century Euclidean Geometry, MAA, 1995.

The Symmedians

  1. Symmedian and 2 Antiparallels
  2. Symmedian and Antiparallel
  3. Symmedian in a Right Triangle
  4. Nobbs' Points and Gergonne Line
  5. Three Tangents Theorem
  6. A Tangent in Concurrency
  7. Symmedian and the Tangents
  8. Bride's Chair
  9. Star of David
  10. Ceva's Theorem
  11. The Many Ways To Construct a Triangle
  12. Concyclic Circumcenters: A Dynamic View
  13. Concyclic Circumcenters: A Sequel

Copyright © 1996-2009 Alexander Bogomolny

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