Let H be the orthocenter of
ABC. Then A is the orthocenter of
BCH, and similarly for B and C. This observation leads to a curious fact that all four triangles share the 9-point circle. In
ABC the 9-point circle passes through the midpoints of the sides, the feet of the altitudes and the Euler points, i.e., the points midway from the orthocenter to the vertices.
Now, by Feuerbach's theorem, the 9-point circle is tangent to the incircle of a triangle and its excircles. It follows, that in a configuration of four points A, B, C, H and four triangles ABC, ABH, BCH, CAH, the same circle (the 9-point circle of all four triangles) is tangent, in general, to sixteen circles: