Angle Bisectors On Circumcircle
What is this about?
A Mathematical Droodle
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Copyright © 1996-2018 Alexander Bogomolny
The applet attempts to suggest the following problem [Tao, pp. 50-51]:
ABC is a triangle that is inscribed in a circle. The angle bisectors of A, B, C meet the circle in D, E, F, respectively. Show that AD is perpendicular to EF.
We'll concentrate on ΔFIM.
By a theorem of the inscribed angles,
∠IFM = ∠CFE = ∠CBE = ∠B/2.
By a the theorem of the secant angles (or with the help of the Exterior Angle Theorem),
∠FIM = ∠ACI + ∠CAI = ∠C/2 + ∠A/2.
It follows that in ΔFIM, angles at F and I add up to 90°:
∠A/2 + ∠B/2 + ∠C/2 = 180°/2 = 90°.
We conclude that the remaining angle at M is necessarily right.
References
- T. Tao, Solving Mathematical Problems, Oxford University Press
|Activities| |Contact| |Front page| |Contents| |Geometry|
Copyright © 1996-2018 Alexander Bogomolny
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