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Six Incircles in an Equilateral Triangle: What is it about?
A Mathematical Droodle


This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at http://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.


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What if applet does not run?

Explanation

Copyright © 1996-2009 Alexander Bogomolny

 

 

 

 

 

 

 

 

 

 

 

 

 

 

The applet purports to illustrate one of the many properties of an equilateral triangle.

Let M be a point inside an equilateral triangle ABC, with pedal points A', B', and C', as shown. The lines joining M to the six points split the triangle into six smaller ones. Circles are inscribed into each of the latter.


This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at http://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.


Buy this applet
What if applet does not run?

If the diameter of the incircle of triangle UVW is denoted D(UVW), the applet suggests that

(1) D(AMB') + D(BMC') + D(CMA') = D(A'MB) + D(B'MC) + D(C'MA).

For a proof, note that all six triangles are right, with the right angles at the pedal points A', B', C'. For a right triangle with legs a and b and the hypotenuse c, the inradius r is determined by

(2) 2r = a + b - c,

see the diagram in the Proof #33 of the Pythagorean proposition. With (2) in mind, (1) reduces to

(3) AB' + BC' + CA' = A'B + B'C + C'A.

Draw AbAc||BC, BaBc||AC, and CaCb||AB. This gets us three equilateral triangles with the pedal points A', B', C' as the midpoints of their bases. That is to say,

(4) A'Bc = A'Cb
B'Ca = B'Ac
C'Ab = C'Ba.

Substituting (4) into (3) and noting that, e.g., AB' = ACa + CaB', we get the following equivalent for (3)

(5) ACa + BAb + CBc = BCb + CAc + ABa.

Finally observe that

(6) ACa = BCb
BAb = CAc
CBc = ABa,

which proves (5).

References

  1. T. Andreescu, B. Enescu, Mathematical Olympiad Treasures, Birkhäuser, 2004

Copyright © 1996-2009 Alexander Bogomolny

33058687Page copy protected against web site content infringement by Copyscape


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