Represent 6 with 3 identical digits using only the usual arithmetic operations, factorials and square roots

Solution

(1 + 1 + 1)! = 6
2 + 2 + 2 = 6
3×3 - 3 = 6
√4 + √4 + √4= 6
5/5 + 5 = 6
6×6/6 = 6
7 - 7/7 = 6
8 - √(√(8 + 8))= 6
√(9×9) - √9 = 6
(0! + 0! + 0!)! = 6

Both the problem and its solution have been submitted by Tobias Danielsson.


Related material
Read more...

  • Funny Arithmetic
  • A single formula to express all numbers
  • Any Integer with Three 2s
  • Representation of numbers with a single 4. The rules and the possibilities
  • One 4, a story
  • Three 3's
  • Representation of numbers with three 4's
  • Representation of numbers with three 5's
  • Representation of numbers with four 3's
  • Representation of numbers with four 4's
  • Representation of numbers with four 5's
  • A problem of representing 4 by four identical digits
  • A problem of representing 6 by three identical digits
  • A 9's Fan's Clock
  • Make an Identity
  • Fun with numbers: place plus/minus signs between the digits
  • 24 with One Digit
  • Representation of 3 with Three Equal Digits

    • |Contact| |Front page| |Contents| |Algebra|

     

    Copyright © 1996-2018-1996-2001 Alexander Bogomolny

    74385980