# Represent 6 with 3 identical digits using only the usual arithmetic operations, factorials and square roots ### Solution

 (1 + 1 + 1)! = 6 2 + 2 + 2 = 6 3×3 - 3 = 6 √4 + √4 + √4 = 6 5/5 + 5 = 6 6×6/6 = 6 7 - 7/7 = 6 8 - √(√(8 + 8)) = 6 √(9×9) - √9 = 6 (0! + 0! + 0!)! = 6 Both the problem and its solution have been submitted by Tobias Danielsson. • Funny Arithmetic
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