Represent 6 with 3 identical digits using only the usual arithmetic operations, factorials and square roots

Solution

(1 + 1 + 1)! = 6
2 + 2 + 2 = 6
3×3 - 3 = 6
4 + 4 + 4= 6
5/5 + 5 = 6
6×6/6 = 6
7 - 7/7 = 6
8 - ((8 + 8))= 6
(9×9) - 9 = 6
(0! + 0! + 0!)! = 6

Both the problem and its solution have been submitted by Tobias Danielsson.


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