# Represent 6 with 3 identical digits using only the usual arithmetic operations, factorials and square roots

### Solution

(1 + 1 + 1)! | = 6 |

2 + 2 + 2 | = 6 |

3×3 - 3 | = 6 |

√4 + √4 + √4 | = 6 |

5/5 + 5 | = 6 |

6×6/6 | = 6 |

7 - 7/7 | = 6 |

8 - √(√(8 + 8)) | = 6 |

√(9×9) - √9 | = 6 |

(0! + 0! + 0!)! | = 6 |

Both the problem and its solution have been submitted by Tobias Danielsson.

|Contact| |Front page| |Contents| |Algebra|

Copyright © 1996-2018-1996-2001 Alexander Bogomolny

71410740