# Equidecomposition of a Triangle and a Rectangle II

A triangle is equidecomposable with a rectangle. Based on such a decomposition one can easily obtain the basic formula for the Area of Parallelogramarea of a triangle: *base* × *altitude* = *twice the area*.*area* = *semiperimeter* × *inradius*

What if applet does not run? |

### Equidecomposition by Dissiection

- Carpet With a Hole
- Equidecomposition of a Rectangle and a Square
- Equidecomposition of Two Parallelograms
- Equidecomposition of Two Rectangles
- Equidecomposition of a Triangle and a Rectangle
- Equidecomposition of a Triangle and a Rectangle II
- Two Symmetric Triangles Are Directly Equidecomposable
- Wallace-Bolyai-Gerwien Theorem
- Perigal's Proof of the Pythagorean Theorem
- A Proof Perigal and All Others After Him Missed
- Dissection of a Vase
- Curvy Dissection

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny

63238137 |