Representing numbers as a result of arithmetic operations on a restricted set of numbers is an entertaining activity (Three 3's, Three 4's, Three 5's, Four 3's, Four 4's, Four 5's) that even lends itself to some degree of systematization. Since the basic arithmetic operations take two arguments (a+b, a*b, ab, etc.), it never occurred to me to consider representing numbers with a single selected number. For instance, 1 = [3], 2 = [3!], 3 = 3. However, I received the following letter from one of the visitors:
I have been interested in this puzzle for thirty years. Is it possible
to represent the numbers 1 - 12 mathematically only using 1 four?
Well, there are at least two ways to look at the table. For one, I'll use it as an index to introduce the number families referred to by Robert (Fibonacci numbers, Bell numbers, ...). Secondly, since accepting notations that index such families of numbers (e.g., F4) would mean going beyond the original problem of representing numbers with arithmetic operations, I consider this a challenge to put up a similar table while staying in the framework of arithmetic operations.
Below are the results of my first attempt. You are welcome to suggest more entries. I would still allow for supefactorial and subfactorial notations, although they are far from being standard. To shorten the representations, I shall use the conventions introduced for the same purpose elsewhere. Thus {n} refers to an entry in row #n provided, of course, it has already been filled. (exp(x) = ex and its inverse ln(x) are being used somewhat reluctantly.)
The number was discovered independently by Niclaus Bernoulli and L.Euler. The idea of derangements is exemplified in a concrete form by the following problem of misaddressed letters:
Someone writes n letters and prepares n envelopes with the corresponding addresses. How many ways are there of placing all the letters into the wrong envelopes?
Vladimir also notes that the fourth Lucas number L4 = 7. Lucas numbers are defined by the same recurrence formula as Fibonacci numbers: Ln+1 = Ln + Ln-1 but with a different seed (L1 = 1,L2 = 3) as opposed to the Fibonacci sequence seed (F1 = 1,F2 = 1).