Cut the knot: learn to enjoy mathematics
A math books store at a unique math study site. Learn to enjoy mathematics.
Google
Web CTK
Best sites for teachers
Sites for teachers
Sites for parents
Terms of use
Awards

Interactive Activities
CTK Exchange
CTK Insights - a blog

Games & Puzzles
What Is What
Arithmetic/Algebra
Geometry
Probability
Outline Mathematics
Make an Identity
Book Reviews
Eye Opener
Analog Gadgets
Inventor's Paradox
Did you know?...
Proofs
Math as Language
Things Impossible
Visual Illusions
My Logo
Math Poll
Cut The Knot!
MSET99 Talk
Other Math sites
Front Page
Movie shortcuts
Personal info
Reciprocal links
Privacy Policy

Guest book
News sites

Recommend this site

Best sites for teachers
Sites for teachers
Sites for parents

Education & Parenting

Manifesto: what CTK is about Search CTK Buying a book is a commitment to learning Table of content Things you can find on CTK Chronology of updates Email to Cut The Knot Recommend this page

Complex Numbers

  1. Algebraic Structure of Complex Numbers
  2. Division of Complex Numbers
  3. Useful Identities Among Complex Numbers
  4. Useful Inequalities Among Complex Numbers
  5. Trigonometric Form of Complex Numbers
  6. Real and Complex Products of Complex Numbers
  7. Complex Numbers and Geometry
  8. Remarks on the History of Complex Numbers
  9. Complex Numbers: A Dynamic Tool
  10. Cartesian Coordinate System
  11. Fundamental Theorem of Algebra
  12. Complex Number To a Complex Power May Be Real
  13. One Can't Compare Two Complex Numbers
  14. Problems

Trigonometric Form of Complex Numbers

Except for 0, any complex number can be represented in the trigonometric form or in polar coordinates:

  z = r(cosa + i·sina),

where aArg(z). r, the modulus, or the absolute value of z, is easy to find:

  .

But how do we find a? As we know, a is not unique, but is found modulo 2p. The main value, arg(z) belongs to the interval [0, 2p). Assume, z = x + yi. Then a is the angle formed with the x-axis by the radius vector of the point (x, y) or the point where the latter intersects the unit circle, viz.,

  z/|z| = cosa + i·sina.

Apparently, a can be found from

(1) tana = y/x.

While this is correct to a great extent, caution should be exercised. Obviously, (1) does not work for x = 0. x = 0 is clearly an exceptional case, but even in that case we face two alternatives of assigning to arg(z) either p/2 or 3p/2. The choice depends on the sign of y. (For y = 0, z = 0 and, as we know, 0 is the only complex number not associated with any argument.)

 
arg(z) = p/2, y > 0,
arg(z) = 3p/2, y < 0.

Similar consideration must be brought to bear in the general case (1), where x ≠ 0. Since tan() is periodic with period p and the base interval (-p/2, p/2), we'll have to account for the signs of both x and y.

In the quadrants I and III, tan(t) is positive. In the quadrants II and IV, tan(t) < 0. In quadrant I, arg(z) = arctan(y/x). But, for quadrant III, the positive arctan(y/x) must be upgraded with the addition of p. Similarly, for z in quadrant II, arctan(y/x) is negative. To bring it to the second quadrant we have to add p. For z in the fourth quadrant, arctan(y/x) is again negative, but its location is correct. To keep it there we now have to add 2p, so that the value falls into the interval [0, 2p). To sum up, denote a0 = tan(y/x). Then

 
arg(z) = a0, x > 0, y > 0,
arg(z) = a0 + p, x < 0, y > 0,
arg(z) = a0 + p, x < 0, y < 0,
arg(z) = a0 + 2p, x > 0, y < 0,

or in a shorter form,

 
arg(z) = a0, x > 0, y > 0,
arg(z) = a0 + 2p, x > 0, y < 0,
arg(z) = a0 + p, x < 0.

The trigonometric form is intimately related to the operation of multiplication. Let z = r(cosa + i·sina) and w = s(cosb + i·sinb). Then

(2)
zw= rs(cosa + i·sina)(cosb + i·sinb)
 = rs(cos(a + b) + i·sin(a + b).

The latter follows from the definition of the multiplication of complex numbers and the addition formulas for sine and cosine.

  cos(a + b) = cosa·cosb - sina·sinb and
sin(a + b) = sina·cosb + cosa·sinb.

(2) tells us that the modulus of the product of two numbers is the product of their moduli, something we already knew. But it also tells us something we did not: the argument of the product is the sum of the arguments of the multiplicands. (The latter of course needs to be taken modulo 2p.)

(3+) |zw| = |z||w| and
arg(zw) = arg(z) + arg(w) (mod 2p).

Colloquially, to multiply two complex numbers one has to multiply their absolute values and add their arguments.

It is easy to see that arg(z') = -arg(z) (mod 2p). From which we conclude that, for w ≠ 0,

(3-) |z/w| = |z|/|w| and
arg(z/w) = arg(z) - arg(w) (mod 2p).

By induction, (3+) and (3-) imply de Moivre's identity: for any integer n ≠ 0,

  (cosa + i·sina)n = cos(na) + i·sin(na).

For n = 0 and z ≠ 0, we define z0 = 1 and then de Moivre's formula holds for all integer n, with no exception. In general, (2) leads to

(4) [r(cosa + i·sina)]n = rn[cos(na) + i·sin(na)].

(As a matter of fact, see [Kline, p. 408], de Moivre has stated the eponymous formula only implicitly. Its standard form is due to Euler and was generalized by him to any real n.)

Next, let's think of what it takes to evaluate roots of complex numbers. It is clear form (4), that, for a given w, choosing |z| = |w|1/n and arg(z) = arg(w)/n will solve the problem, w = zn:

 
zn= [|w|1/n(cos(arg(w)/n) + i·sin(arg(w)/n))]n
 = |w|n·1/n(cos(n·arg(w)/n) + i·sin(n·arg(w)/n))
 = |w|(cos(arg(w)) + i·sin(arg(w)))
 = w.

The important thing to note is that, save for the trivial case n = 1, we can get additional roots. For example, we might have chosen arg(z) = (arg(w) + 2p)/n with exactly the same effect. Indeed, since both cosine and sine have period 2p, we would have

 
zn= [|w|1/n(cos((arg(w) + 2p)/n) + i·sin((arg(w) + 2p)/n))]n
 = |w|(cos(arg(w) + 2p) + i·sin(arg(w) + 2p))
 = w.

Even more generally, for an integer k and arg(z) = (arg(w) + 2kp)/n, we have

(5)
zn= [|w|1/n(cos((arg(w) + 2kp)/n) + i·sin((arg(w) + 2kp)/n))]n
 = |w|(cos(arg(w) + 2kp) + i·sin(arg(w) + 2kp))
 = w.

Of course, some k will produce the same complex numbers. For example, if m = k + n, then

 
(arg(w) + 2mp)/n= (arg(w) + 2(k + n)p)/n
 = (arg(w) + 2kp + 2np)/n
 = (arg(w) + 2kp)/n + 2p
 = (arg(w) + 2kp)/n (mod 2p),

so that k and m define exactly the same complex number. Well, we see that in (5) not all numbers are different. But how many are? The answer is n! Which means that, for any complex numbers w, the equation zn = w has n different roots! This is all because the argument of a complex number is only defined modulo 2p. For example, if n = 4, then in the sequence

  arg(w)/n,
(arg(w) + 2p)/4,
(arg(w) + 4p)/4,
(arg(w) + 6p)/4,
(arg(w) + 8p)/4, ...

the fifth term (i.e. the one with the coefficient 8) equals modulo 2p the first term and, starting with that term, the sequence repeats itself having modulo 2p only four distinct terms.

This is not so surprising. After all, we were solving zn = w which is a polynomial equation of order n. According to the Fundamental Theorem of Algebra, any polynomial equation with real (in fact, complex) coefficients, has exactly n roots.

We may also draw on our real numbers experience. For any positive real number a, there are two square roots, a and -a. As complex numbers, the first (i.e. positive) one has argument 0, the second (negative) has argument p. I.e., for a positive real number a,

  arg(a) = 0,
arg(-a) = p.

Example

Let's find all the third roots of w = 8 - 8i. In the trigonometric form, w = 8(cos(3p/4) + i·sin(3p/4)). Thus we get three distinct roots:

  2(cos(p/4) + i·sin(p/4)),
2(cos(p/4 + 2p/3) + i·sin(p/4 + 2p/3)),
2(cos(p/4 + 4p/3) + i·sin(p/4 + 4p/3)).

Recollecting that p = 180o, we get the three roots in a little different form:

  2(cos(45o) + i·sin(45o)),
2(cos(165o) + i·sin(165o)),
2(cos(285o) + i·sin(285o)),

all evenly spaced around the origin.

References

  1. T. Andreescu, D. Andrica, Complex Numbers From A to ... Z, Birkhäuser, 2006
  2. C. W. Dodge, Euclidean Geometry and Transformations, Dover, 2004 (reprint of 1972 edition)
  3. Liang-shin Hahn, Complex Numbers & Geometry, MAA, 1994
  4. M. Kline, Mathematical Thought From Ancient to Modern Times, v. 2, Oxford University Press, 1972
  5. E. Landau, Foundations of Analisys, Chelsea Publ, 3rd edition, 1966

Copyright © 1996-2008 Alexander Bogomolny

28697386Page copy protected against web site content infringement by Copyscape


Search:
Keywords:


Latest on CTK Exchange
Math
Posted by Laura
2 messages
06:56 AM, Apr-15-08

Divisibility rules - Jargon buste ...
Posted by Carolyn
2 messages
08:35 AM, Apr-04-08

drawing puzzle
Posted by martin gran
31 messages
06:53 PM, May-09-08

Distance to the horizon
Posted by Monty
3 messages
04:38 PM, May-08-08

Mistake on the page (an aside, Be ...
Posted by Max
4 messages
10:28 AM, Feb-28-08

Deriving functions based on diffe ...
Posted by ke_45
1 messages
12:47 PM, May-10-08

A typo in
Posted by alexwajn
1 messages
11:36 PM, Apr-19-08