The Broken Chord Theorem
Proof by Mariano Perez de la Cruz

On the circumcircle of triangle ABC, point P is the midpoint of the arc ACB. PM is perpendicular to the longest of AC or BC. Prove that M divides the broken line ACB in half.
broken chord theorem by Mariano Perez de la Cruz

Proof

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Copyright © 1996-2018 Alexander Bogomolny

On the circumcircle of triangle ABC, point P is the midpoint of the arc ACB. PM is perpendicular to the longest of AC or BC. Prove that M divides the broken line ACB in half.
broken chord theorem by Mariano Perez de la Cruz

By extending PM to its intersection with the circumference we get point S. A line from S through B intersects the AC extended in F.

∠MSA = ∠MSF since P bisects the original arc AB, implying AM = MF.

We are to prove that CF = CB.

This is so because, ∠CBF is suplementary of ∠CBS, and, since ACBS is an inscribed quadrilateral, ∠CAS = ∠CFB, both being suplementary to ∠CBS. Therefore CF = CB.

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|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny
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