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Three 5's
| 1 |
√5·√5/5=(5·5)&5 |
| 2 |
(5+5)/5 |
| 3 |
√5·√5-[√5] = 5·.5 + .5 (2) |
| 4 |
5-5/5 |
| 5 |
5·5/5=5/.5-5 |
| 6 |
5+5/5=5+.5+.5 |
| 7 |
√5·√5+[√5] |
| 8 |
5/.5-[√5] |
| 9 |
√5·√5/.(5) |
| 10 |
√5·√5/.5=5<<(5/5) |
| 11 |
55/5 |
| 12 |
5/.5+[√5] |
| 13 |
[√5+5·√5] |
| 14 |
5/.(5)+5 |
| 15 |
5+5+5 |
| 16 |
5!!+5/5 |
| 17 |
5!!+[5/√5] |
| 18 |
5!!+5-[√5] |
| 19 |
5!!+5-[√√5] |
| 20 |
5!!+√5·5] |
| 21 |
5!!+5+[√√5] |
| 22 |
5!!+5+[√5]=[5·5-√5] |
| 23 |
5·5-[√5] |
| 24 |
(5-5/5)! |
| 25 |
5!! + 5 + 5(1) |
| 26 |
5·5+[√√5] |
| 27 |
5·5+[√5] |
| 28 |
[√5]·[√5! + √(√5!)](3) |
| 29 |
[5·5·√√√√√5!](3) = 5!/5 + 5(3) |
| 30 |
5·5+5 |
| 31 |
31=[(√5! + 5) * [√5]](3) |
| 32 |
5!!/.(5)+5 |
(1) By Andre Gustavo dos Santos, Brasil
(2) By my son, David
(3) By Iulianos Kakulidis, Greece
Copyright © 1996-2009 Alexander Bogomolny
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