Napoleon's Theorem by Plane Tessellation
We already have several proofs of Napoleon's Theorem and its generalizations. Here is an illustration of another one that is somewhat akin to the second proof by Scott Brodie but (to me is) more revealing.
The given triangle is the one at whose vertices I placed red dots. (These are moveable so that you must be able to modify the triangle.) It appears that the triangle and the attached Napoleon's triangles form a starting configuration for a simple tessellation of the plane. Napoleon's triangles have different backgrounds. To clarify the argument, pick two colors and erase all other triangles. Then it becomes quite obvious that the centers of triangles of a single color form a hexagonal lattice (black lines).
Centers of all other triangles lie at the centers of the lattice triangles. In the diagram, all such points are connected by greenish lines. The greenish lines form a finer lattice (a lattice with more points.) Centers of all Napoleon's triangles lie at nodes of the latter lattice. This proves the theorem.
Various plane tessellations are discussed in a recent book Dissections: Plane & Fancy (Cambridge University Press, 1997) by Greg Frederickson from Purdue University. Although Napoleon's theorem is not mentioned in the book, you can get a sense how this approach applies to other problems. For another example you are referred to the proof of Pythagoras' Theprem by K.O.Friedrichs.
Reference
- P.Scott, Some Recent Discoveries in Elementary Geometry, The Math Gazette, 1998, pp 391-397
- J.F.Rigby, Napoleon Revisited, J of Geometry, 33 (1988) pp 129-146
Napoleon's Theorem
Copyright © 1996-2008 Alexander Bogomolny
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