Date: Thu, 30 Jul 1998 16:47:18 -0400

From: Alex Bogomolny

On a single toss, the probability of not getting, say 1, is 5/6. On two tosses it's (5/6)*(5/6). On three tosses, it's (5/6)*(5/6)*(5/6), etc.

The probability goes to 0 as the number of tosses grows. For an infinite number of tosses it is 0. However, in principle, i.e., if it were possible to perform an infinite number of tosses, it would be possible, I expect, not to have 1 at all, even though the probability of such an event is 0.

Best regards,

Alexander Bogomolny

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