Subject: Re: J.J.Sylvester's puzzle
Date: Tue, 9 Dec 1997 21:51:50 -0500
From: Alex Bogomolny
One solution to your problem appears on p282 of M.Gardner's Time Travel. This is one of the problems on which J.J.Sylvester spent his last years, not just three days. Number 9 points:
Now stretch the upper and bottom rows symmetrically so that points 368, 148, 269, and 247 form four lines. Other six: 123,456,789,258,357,159.