Squaring Numbers in Range 26-50

Let A be such a number. Subtract 25 from A to get x. Subtract x from 25 to get, say, a. Then A² = a² + 100x. For example, if A = 26, then x = 1 and a = 25 - 1 = 24. Hence

26² = 24² + 100 = 676.

Similarly, if A = 37, then x = 37 - 25 = 12, and a = 25 - 12 = 13. Therefore,

37² = 13² + 100·12 = 1200 + 169 = 1369.

Why does this work?

(25 + x)² - (25 - x)²= [(25 + x) + (25 - x)]·[(25 + x) - (25 - x)]
 = 50·2x
 = 100x.

Another way: recollect that (a ± b)² = a² ± 2ab + b². This leads to the following derivation:

(25 + x)² - (25 - x)²= [25² + 50x + x²] - [25² - 50x + x²]
 = [625 -625] + [x² - x²] + [50x + 50x]
 = 100x.

Either way, it follows that

(25 + x)²= (25 - x)² + 100x.


Related material
Read more...

  • Multiplication by 9, 99, 999, (Multiply + Subtract) etc.
  • Squaring 2-Digit Numbers
  • Division by 5
  • Multiplication by 2
  • Multiplication by 5
  • Multiplication by 9, 99, 999, etc. (Something Special)
  • Product of 10a + b and 10a + c where b + c = 10
  • Product of numbers close to 100
  • Product of two one-digit numbers greater than 5
  • Product of 2-digit numbers
  • Squaring Numbers in Range 51-100
  • Squares of Numbers That End in 5
  • Squares Can Be Computed Squentially
  • How to Compute Fast Any Square
  • Adding a Long List of Numbers

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