# Monge from Desargues

Monge's theorem (Monge's Circle Theorem, Three Circles Theorem) claims that,

given three circles of distinct radii situated entirely in each other's exterior, then the three points of intersection of the pairs of external common tangents are collinear.

(The theorem is valid even if the circles intersect and has a sensible interpretation when two or three circles have the same radius.)

Following is a proof derived from Desargues' theorem.

Denote the centers of the three circles as A, B, C. Let A', B', C' be the intersections of the common tangents external to ΔABC, see the applet. In ΔA'B'C' the lines AA', BB', CC' serve as bisectors of angles A', B', and C', respectively. Therefore, the three lines concur at the incenter (I') of ΔA'B'C'. This shows that the two triangles ABC and A'B'C' are perspective from a point. By Desargues' theorem, they are also perspective from a line.

### Remark

There is by far a more direct derivation of Monge's theorem from Desargues' theorem.

### References

- J. McCleary,
__An Application of Desargues' Theorem__,*Mathematics Magazine*, Vol. 55, No. 4 (Spet., 1982), 233-235.

### Monge's Theorem

- Three Circles and Common Tangents
- Monge from Desargue
- Monge via Desargue

### Desargues' Theorem

- Desargues' Theorem
- 2N-Wing Butterfly Problem
- Cevian Triangle
- Do You Speak Mathematics?
- Desargues in the Bride's Chair (with Pythagoras)
- Menelaus From Ceva
- Monge from Desargues
- Monge via Desargue
- Nobbs' Points, Gergonne Line
- Soddy Circles and David Eppstein's Centers
- Pascal Lines: Steiner and Kirkman Theorems II
- Pole and Polar with Respect to a Triangle
- Desargues' Hexagon
- The Lepidoptera of the Circles

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny

71924658