## E. W. Dijkstra's Proof of the Pythagorean Theorem

The essence of Dijkstra's approach to the old theorem is less an elegant proof than a novel formulation. Dijkstra's formulation serves a bridge to the Law of Cosines but even more curiously it focuses on the comparative properties of all angles of a triangle instead of a customary consideration of a single angle, which is required to be right for the Pythagorean theorem or anything else for the Law of Cosines or generalizations.

If, in a ΔABC, angles α, β, γ lie opposite the sides of length a, b, c, then

sign(α + β - γ) = sign(a² + b² - c²), |

where sign(t) is the signum function.

What if applet does not run? |

Dijkstra constructs two additional lines CL and CN so that

BCN = CAB and ACL = CBA |

which makes triangles ABC, ACL and BCN similar and angles ALC and BNC equal. At the vertex C we now find and may compare all three angles α, β, γ of ΔABC. Dijkstra's original diagram only deals with the case where

Area(ACL) + Area(BCN) < Area(ABC). |

In view of α + β + γ = 180°,

Finally, wherever α + β - γ > 0, the two triangle ACL and BCN overlap. It is even possible just for one of them to cover ΔABC completely. In any event, if α + β - γ > 0 we have

Area(ACL) + Area(BCN) > Area(ABC). |

So in all cases,

sign(α + β - γ) = Sign(Area(ACL) + Area(BCN) - Area(ABC)). |

To finish the proof, one only needs to observe that the areas of similar triangles are in the same proportion as the squares of any of their corresponding elements. In particular, picking up the sides opposite the angle equal to γ

Area(ACL) / a² = Area(BCN) / b² = Area(ABC) / c², |

or

Area(ACL) = ka², Area(BCN) = kb², Area(ABC) = kc² |

for some positive k. Which leads directly to Dijkstra's claim:

sign(α + β - γ) = sign(a² + b² - c²). |

Intuitively clear as Dijkstra's proof may be, not everyone finds it simple enough. I have received the following from Mr. Guoping Zeng, Ph.D. in Math, Sr. Software Engineer, Adjunct Professor, UT Dallas:

The geometric proof of Dijkstra's generalization of the Pythagorean theorem is too complicated. Moreover, the figure for the case is not easy to draw considering many cases: Indeed, the following algebraic proof by means of the Law of Cosines is much simpler and nicer. Algebraic Proof (G. Zeng): Since α + β + γ = π, we have
By the Law of cosines, c² = a² + b² - 2ab cosγ. Re-arranging the terms yields
Taking the sign function on both sides, we have
Since cos γ is positive, zero and negative when
Substituting (4) into (3) yields
Comparing (5) and (1) yields
Q.E.D. |

As often is done in mathematics, see for example a discussion in [D. Ruelle, *The Mathematician's Brain*], mathematicians help their thinking and interpersonal communication by relying on unique concepts that incorporate and, thus, hide the complexity of the constructions based on first principles. Seldom mathematicians derive their results directly from some fundamental axioms. Instead, they use already proven theorems and suitable definitions. For example, the *cosine* function embodies the idea of similarity, as characterized by shape properties of triangles, and sign switching depending on the size of angle γ implicit in Euclid II.12 and II.13. The Law of Cosines, too, admits multiple proofs that do not rely on the Pythagorean theorem so that Dr. Zeng's proof does not include any circularity and constitutes a valid derivation of Dijkstra's identity.

|Up| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny69636012