Pedal Similarity

What Might This Be About?

26 December 2014, Created with GeoGebra

Statement

Let $P$ be a point in the plane of $\Delta ABC;$ $A',B',C'$ the intersections of $AP,BP,CP$ with the circumcircle $(ABC).$ $\Delta DEF$ is the pedal triangle of $P$ relative to $\Delta ABC.$

pedal and circumcevian triangles of the same point are similar

Triangles $DEF$ and $A'B'C'$ are similar.

Proof

Triangle $A'B'C'$ is known as the circumcevain triangle of point $P,$ and the property at hand has been established elsewhere by elegant and characteristic of the situation angle chasing. Below, I use another form of angle chasing with a reference to a different page.

pedal and circumcevian triangles of the same point are similar

In deriving the formula for $[\Delta DEF]$ we found that $\angle EDF=\angle ACB'.$ But, as two inscribed angles subtended by the same chord, $\angle B'CC'=\angle B'A'C'.$ By transitivity of equality $\angle EDF=\angle B'A'C'.$ Similarly, $\angle DEF=\angle A'B'C'$ and $\angle DFE=\angle A'C'B'.$

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