Subject: Integration in Spherical Coordinates of a cube
Date: Sun, 17 Nov 1996 11:27:06 -0800
From: "Émerick Arteche Gallego"

HI ALEX,

I have been presented with the following problem: Find the Triple integral of a cube in spherical coordinates defined by the intersection of the following planes: x= plus or minus 1/2; y= plus or minus 1/2; z=plus or minus 1/2

My initial attempt was to trisect the cube that resides in the first octant, multiply it by 24, and hopefully get an answer of 1. The limits of integration I used for theta, phi, and rho are the following:

0 < theta < Pi/4
Pi/4 < phi < Pi/2
0 < rho < (sec (theta)*csc(phi))/2

However this didn't work. I get an answer of 1.14 . . . . with Maple V.

Could you tell me what wrong?

Thanks in advance,

Emerick
____________________

Math joke of the Week:

1 + 1 = 3

For large values of 1.

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