Subject: Re: Pythagorean triples
Date: Tuesday, December 17, 1996 7:39 PM
From: Alex Bogomolny

You can check that for any m > n the following is true:

(m2-n2)2 + (2mn)2 = (m2+n2)2

so that the numbers (m2-n2), 2mn, and (m2+n2) always form a Pythagorean triple.

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