Subject: Re: Number series
Date: Wed, 9 Apr 1997 21:49:32 -0400
From: Alexander Bogomolny
the prompt must not be the best. You are right: it's 1414. For 1414*1415/2 = 1000405. Where was the error?
: The sum of all numbers from 1 through n equals Sn = n(n+1)/2. : You are looking for an n such that Sn < 1000000 but : Sn+1 > 1000000. This number is 1413.
The right way actually is this: You are looking for n such that Sn > 1000000 but Sn-1 < 1000000.
Getting sqrt(2000000) is approximately 1414.2... So n=1414 How do you get it? (n-1)*n < 2000000 < n*(n+1).
Taking sqrt(2000000) and rounding it to 1414 is only suggestive and must yet be verified. Because we do not know from the above two inequalities whether 1414^2 is more or less than 1000000.
To convince yourself think of 11 instead of 1000000:
5 is the first n such that n(n+1)/2 > 11. According to my original answer you were supposed to look for the largest n for which still n(n+1)/2 < 11. This would give n = 4.
With apologies from
East Brunswick, NJ, USA