Date: Wed, 26 Mar 1997 23:47:32 -0500

From: James H.

Alex, thank you for pointing out where I "screwed up." Resolved the tableau;

The whole problem reads:

Use the simplex method to solve the following: Maximize: Z = 2x1 - 6x2 [the 1 & 2 after the x are lowered] subject to: x1 - x2 <_ 4, -x1 + x2 <_ 4, x1 + x2 <_ 6, x1,x2 >_ 0 the first tableau: Max. Z = 2x1 - 6x2 + 0s1 + 0s2 + 0s2 x1 x2 s1 s2 s3 Cb\Cj 2 -6 0 0 0 s1 0 1 -1 1 0 0 4 pivot row s2 0 -1 1 0 1 0 4 s3 0 1 1 0 0 1 6 Zj 0 0 0 0 0 0 Cj-Zj 2 -6 0 0 0 pivot columm

Then, ? I am lost! Can you help?

James