# Find the Center of a Given Circle

### Problem

Construct the center of a given circle.

## Solution We are given a circle. Point G will be shown to be its center. We proceed in several steps:

1. On the arc, choose a point A. With A as a center and an aribtrary radius, draw circle I that intersects the given arc at two points - B and D.
2. Use Problem #1 to construct the point C such that BC forms a diameter of the circle I.
3. With the radius CD draw two circles - one centered at A, another at C, and denote by E the point of their intersection.
4. Draw a circle of radius CD centered at E. This intersects the circle I at point F.
5. Now, the segment BF is the radius of the given circle whereas the two circles drawn with this radius and centers at B and A intersect at its center.

## Proof

The isosceles triangles ACE and AEF are congruent, therefore ∠EAF = ∠ACE. Further, ∠BAE = ∠ACE + ∠AEC for ∠BAE is an exterior angle of the triangle ACE. Also, ∠BAE = ∠BAF + ∠EAF. Which gives ∠BAF = ∠AEC.

Thus, the isosceles triangles ABF and ACE are similar which implies BF/AB = AC/CE or BG/AB = AC/CD. It follows from the latter that the isosceles triangles ABG and ACD are also similar and, hence,

 ∠BAG = ∠ACD = ∠BAD/2 = ∠DAG

with the latter two equalities following from the fact that  