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Copyright © 1996-2018 Alexander BogomolnyIn the following we'll assume f(x) is a polynomial with integral coefficients:
Also, the vertical bar (the pipe symbol) is used to indicate divisibility: a|b is a shorthand for "a divides b."
Lemma
For any two different integers p and q,
Proof
Indeed,
and, since (p - q) | (pk - qk) for every integer k>0, Lemma follows.
Assume then that
with all a,b,c, and d different. From Lemma we immediately obtain that
(d - a) | (f(d) - f(a)) = 3 - 2 = 1 | , and |
(d - b) | (f(d) - f(b)) = 3 - 2 = 1 | , and |
(d - c) | (f(d) - f(c)) = 3 - 2 = 1 |
Thus differences d - a, d - b, d - c all divide 1. But 1 has only
two divisors: 1 and -1. Therefore, by the Pigeonhole Principle, two of the differences coincide. Which
contradicts our assumption that the numbers
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