# Parallelogram with Side Lines through Fixed Points

### What Might This Be About?

### Statement

If the four side lines of a parallelogram pass through four collinear fixed points, the diagonals, too, pass through fixed points on the same line:

### Proof

Denote the point involved as below:

By Thales' theorem,

$\displaystyle\frac{FE}{EM}=\frac{CA}{AM}=\frac{HG}{GM},$

or, $\displaystyle\frac{GM}{EM}=\frac{HG}{FE},$

which means that $M$ divides $EG$ in the ratio $HG:FE.$ Since points $E,F,F,H$ are fixed so is that ratio and, therefore, point $M.$ Point $N$ is fixed for the same reason.

### Acknowledgment

In *Exercices de Géométrie* (Jacques Gabay, 1991, #1124, Theorem 322) F. G.-M. credits E. Catalan with this statement.

|Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2018 Alexander Bogomolny63568668 |