angle A is in the xz plane dimentioned from the verticle
angle B is in the yz plane dimentioned from the verticle

to find angle C which is the angle in the xy plane from the verticle the formula is tan(c)=(1/tan(b))*tan(a)

to find the cross section angle which is an angle u would get if u were to saw cut the block of steel through the hole at angle C in the xy plane and view the resulting part from the side perpendicular to the cut. the formula for this angle is

tan(D)=sqrt((tan(A)^2)+(tan(B)^2))

the question is: If I rotate the block of steel 30deg ccw in the yz plane what will be the formulas for angle A, C, D. when B=B+30.

any help will be greatly appreciated.