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Subject: "Functions of more than two varaibles"     Previous Topic | Next Topic
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linda1x4x3
Member since Mar-7-06
Mar-07-06, 10:20 PM (EST)
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"Functions of more than two varaibles"
 
   Suppose that f(x,y,z) = 2x^3 +2y^2 + z
Compute
f(x+h, y+k, z+t) - f(x,y,z)
The answer is 6x^2h + 6xh^2 + 2h^3 + 4yk + 2k^2 + t
I just dont know how they got it.


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alexb
Charter Member
1805 posts
Mar-07-06, 10:21 PM (EST)
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1. "RE: Functions of more than two varaibles"
In response to message #0
 
   >Suppose that f(x,y,z) = 2x^3 +2y^2 + z
>Compute
>f(x+h, y+k, z+t) - f(x,y,z)
>The answer is 6x^2h + 6xh^2 + 2h^3 + 4yk + 2k^2 + t
>I just dont know how they got it.

Just tell what is this expression, f(x+h, y+k, z+t).


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joseph grech
guest
Mar-08-06, 07:25 AM (EST)
 
3. "RE: Functions of more than two varaibles"
In response to message #1
 
   Answer is obviously wrong.z cannot vanish


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mpdlc
guest
Mar-08-06, 07:25 AM (EST)
 
2. "RE: Functions of more than two varaibles"
In response to message #0
 
   I suggest you have a look in your Calculus book about the approximation value of a function in the vecinity of a certain point using TAYLOR Formula.


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Jim
guest
Mar-26-06, 07:00 AM (EST)
 
4. "RE: Functions of more than two varaibles"
In response to message #0
 
   f(x+h, y+k, z+t) - f(x,y,z)
=2(x+h)^3 +2(y+k)^2 + z+t - 2x^3 +2y^2 + z
=6x^2h + 6xh^2 + 2h^3 + 4yk + 2k^2 + t
-Jim


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