|
|
|
|
|Store|
|
|
|
|
CTK Exchange
cleodsc
guest
|
Oct-21-05, 06:41 AM (EST) |
|
"Probability Question"
|
Ok I have an issue I need to prove the following (in notation): P(A)+P(B)-2P(AB)= (Ac U B) U (Bc U A) I know how to prove this using real numbers, for instance knowing P(A)= .5 and P(B)=. 2 and (AB)= .1 which is .5+.2-2(.1)= .5, but I have no idea how to write this using notation. Any ideas?
|
|
Alert | IP |
Printer-friendly page |
Reply |
Reply With Quote | Top |
|
|
alexb
Charter Member
1669 posts |
Oct-21-05, 06:56 AM (EST) |
|
1. "RE: Probability Question"
In response to message #0
|
>Ok I have an issue I need to prove the following (in >notation): P(A)+P(B)-2P(AB)= (Ac U B) U (Bc U A) You probably mean A U B - AB = (Ac B) U (ABc), or P(A U B) - 2P(AB) = P(Ac B) + P(ABc). Venn diagrams are a useful tool that help visualize the situation here. https://www.cut-the-knot.com/LewisCarroll/VennClick.shtml You can use, say, Ac B = B - A = B - AB. Also, (B-AB)·(AB) = empty and (B - AB) U AB = B. So that P(Ac B) = P(B) - P(AB). Similarly, P(ABc) = P(A) - P(AB).
|
|
Alert | IP |
Printer-friendly page |
Reply |
Reply With Quote | Top |
|
|
You may be curious to have a look at the old CTK Exchange archive. Please do not post there.
|Front page|
|Contents|
Copyright © 1996-2018 Alexander Bogomolny
|
|