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Subject: "Pseudo Cardioid Curve"     Previous Topic | Next Topic
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Conferences The CTK Exchange College math Topic #493
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Jeremy
Member since Jan-14-05
Jan-14-05, 02:35 PM (EST)
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"Pseudo Cardioid Curve"
 
   Suppose we have a unit radius circle with center A. We pick a point B on the circumference. We call the intersection of the X-axis on the circumference C. We draw a isosceles triangle formed by the lines AB, BC, CA. Inside this triangle we draw the inscribed circle. Now, keeping point C stationary we sweep the ray AB around the circle repeating this construction for all possible isosceles triangles. This creates an evelope of circles that forms a heart shaped curve that looks like a cardioid. In fact, if you draw this curve and a cardioid together you discover that it is very close to being a cardioid but is not quite. I have managed to determine that the path of the centers of all the inscribed circles lies on the loop part of the right strophoid curve. The part that I haven't solved that I would like to see someone better versed in math than I solve is:

1. What is the equation describing this pseudo cardioid's shape?
2. What is the length of the curve?
3. What is the area of the curve?
4. Does it bear some simple relation to an actual cardioid?
5. Is this a new curve or does it have a name?


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sfwc
Member since Jun-19-03
Jan-16-05, 07:57 PM (EST)
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1. "RE: Pseudo Cardioid Curve"
In response to message #0
 
   >1. What is the equation describing this pseudo cardioid's
>shape?
This is rather ugly, so I shall cover it only in the briefest detail.

Let 2a be the angle CAB, and let t be chosen so that sin a = 2t/(t^2 + 1) and cos a = (t^2 - 1)/(t^2 + 1)

It follows that cos 2a = (t^4 - 6t^2 + 1)/(t^2 + 1)^2
and sin 2a = 4t(t^2 - 1)/(t^2 + 1)^2

Therefore the location of the centre of the incircle is at:

((t - 1)^2/(t^2 + 1), 2t(t - 1)/(t^2 + 1)(t + 1))

and naturally the radius is equal to the y co-ordinate.

Therefore the equation of the incircle is:

x^2 + y^2 - 2*x*(t - 1)^2/(t^2 + 1) - 4*y*t*(t - 1)/((t^2 + 1)*(t + 1)) + ((t - 1)^2/(t^2 + 1))^2 = 0

For the points on the envelope, the derivative of this expression with respect to t must also be 0. This gives us two equations in the variables x and y. Solving with maple and neglecting the solution on the x axis gives:

x = (t^10-t^8-12*t^7+8*t^6+8*t^5+8*t^4-12*t^3-t^2+1)/((t^2+1)*(t^8+2*t^6+2*t^4+2*t^2+1))

y = 2*t*(t^8+2*t^7-2*t^6-6*t^5+6*t^3+2*t^2-2*t-1)/(t^10+3*t^8+4*t^6+4*t^4+3*t^2+1)

since I could see no suitable substitution to simplify this, I will leave the work of calculating the length, area, and so on to those with more guts.

My best guess is that this curve does not have a name.

Thankyou

sfwc
<><


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Graham C
Member since Feb-5-03
Jan-16-05, 07:57 PM (EST)
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2. "RE: Pseudo Cardioid Curve"
In response to message #0
 
   >This creates an evelope of circles that forms a heart shaped
>curve that looks like a cardioid.

I don't really know what you mean by an 'envelope of circles'. I'm used to an 'envelope' being a series of straight lines each tangent to a curve.

If you mean the locus of the centres of the circles, the equation I get is

r = sec(a/2)*tan(pi/4-a/4) / (tan(a/2) plus tan(pi/4-a/4))

but I don't care to integrate it. :-)

And it doesn't look particularly like a cardioid.


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sfwc
Member since Jun-19-03
Jan-17-05, 03:41 PM (EST)
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3. "RE: Pseudo Cardioid Curve"
In response to message #2
 
   >I don't really know what you mean by an 'envelope of
>circles'. I'm used to an 'envelope' being a series of
>straight lines each tangent to a curve.
An envelope can in fact be a series of curves each tangent to a given curve. There is no need for the curves to be straight lines. So you can have an envelope of circles. For example, if you take the set of all circles with centres on a given circle, and passing through a fixed point on that circle, you get a well known envelope. All those circles are tangent to a cardioid.


>If you mean the locus of the centres of the circles, the
>equation I get is
>
>r = sec(a/2)*tan(pi/4-a/4) / (tan(a/2) plus tan(pi/4-a/4))
This, as has been mentioned, is the right strophoid, which has some slightly simpler representations.

Thankyou

sfwc
<><


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Jeremy
Member since Jan-14-05
Jan-17-05, 03:41 PM (EST)
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4. "RE: Pseudo Cardioid Curve"
In response to message #2
 
   If you read my Description again you will see that I already determined the path of the circles as you did and that is not the curve I am talking about. As you construct all of the incircles you will see that their outer boundary starts defining a cardioid type shape as you place ever more circles. That is the curve I am talking about. I don't know how else I can describe it as other than the envelope of a group of circles since the circles (not lines) are forming the outline of the curve. The other post seems to have gotten my intent.


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