>1. What is the equation describing this pseudo cardioid's
>shape?
This is rather ugly, so I shall cover it only in the briefest detail.Let 2a be the angle CAB, and let t be chosen so that sin a = 2t/(t^2 + 1) and cos a = (t^2 - 1)/(t^2 + 1)
It follows that cos 2a = (t^4 - 6t^2 + 1)/(t^2 + 1)^2
and sin 2a = 4t(t^2 - 1)/(t^2 + 1)^2
Therefore the location of the centre of the incircle is at:
((t - 1)^2/(t^2 + 1), 2t(t - 1)/(t^2 + 1)(t + 1))
and naturally the radius is equal to the y co-ordinate.
Therefore the equation of the incircle is:
x^2 + y^2 - 2*x*(t - 1)^2/(t^2 + 1) - 4*y*t*(t - 1)/((t^2 + 1)*(t + 1)) + ((t - 1)^2/(t^2 + 1))^2 = 0
For the points on the envelope, the derivative of this expression with respect to t must also be 0. This gives us two equations in the variables x and y. Solving with maple and neglecting the solution on the x axis gives:
x = (t^10-t^8-12*t^7+8*t^6+8*t^5+8*t^4-12*t^3-t^2+1)/((t^2+1)*(t^8+2*t^6+2*t^4+2*t^2+1))
y = 2*t*(t^8+2*t^7-2*t^6-6*t^5+6*t^3+2*t^2-2*t-1)/(t^10+3*t^8+4*t^6+4*t^4+3*t^2+1)
since I could see no suitable substitution to simplify this, I will leave the work of calculating the length, area, and so on to those with more guts.
My best guess is that this curve does not have a name.
Thankyou
sfwc
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