|
|Store|
|
|
|
|
|
|
|
CTK Exchange
Riddhi
guest
|
May-06-02, 09:35 PM (EST) |
|
"Calculus (Limits)"
|
I am in a dire need for you to answer this Limits question from Calculus. I would greatly appreciate anybody's constructive help ~ I would be really grateful. Use lim (h -> 0) for (f(x+h) - f(x))/(h) to solve the function: f(x) = x ^ (2/3) I would be soooo incredibly happy if you can answer this question! Thanks. ~ Riddhi. |
|
Alert | IP |
Printer-friendly page | Edit |
Reply |
Reply With Quote | Top |
|
|
anshoo
guest
|
May-07-02, 01:53 PM (EST) |
|
1. "RE: Calculus (Limits)"
In response to message #0
|
use the following binomial expansion: (x+h)^n = x^n + (x^(n-1))*n*h + (x^(n-2))*(n(n-1)/2!)*h^2 + .... note that the above expansion holds true even if n is a fraction! |
|
Alert | IP |
Printer-friendly page | Edit |
Reply |
Reply With Quote | Top |
|
|
Michael Klipper
guest
|
Jul-27-02, 02:45 PM (EST) |
|
2. "RE: Calculus (Limits)"
In response to message #0
|
Solve the function for WHAT? For values where f(x) = 0? For a simplified version? If you're looking for a root, x = 0 is the only root. If you're looking for a different representation, then the answer given before me does work. Beware, though, that this representation goes on infinitely. |
|
Alert | IP |
Printer-friendly page | Edit |
Reply |
Reply With Quote | Top |
|
|
You may be curious to visit the old CTK Exchange archive.
|Front page|
|Contents|
|Store|
Copyright © 1996-2018 Alexander Bogomolny
[an error occurred while processing this directive]
|
Advertise
|