Proof of any number is equal to any different number and therefore math is pointless
a, b distinct
then t = a + b then t(a - b) = a² - b² then ta - tb = a² - b² then a² - ta = b² - tb then complete the square on each side and a² - ta + t²/4 = b² - tb + t²/4 and (a - t/2)² = (b - t/2)² and a - t/2 = b - t/2 and a = b QED
QUESTION: What is the earliest reference to this 'proof'?
I don't know, but your proof falls down (at least) because when you square root your completed squares either a-t/2 is negative or b-t/2 is negative. so instead of a-t/2 = b-t/2 you should have a - t/2 = t/2 - b
Don't forget a (non-zero) number will have two square roots!