A short time ago in Mathworld I came across

>
Amazingly, the difference between the areas of the outer and inner Napoleon triangles equals the area of the original triangle (Wells 1991, p. 156).
>

As Johnny Carson used to say 'I did not know that.'

But this is not the reason I write this post.

This fact is a fine raw material for P. theorem proof.

Maybe someone will take pains to prove that the sides

of squares equivalent in area to two Napoleons and the

referrence triangle make a right triangle.

Would make a nice addition to the list, would it not?

Salute,

Maj. Pestich

equivalent squares was a bum steer.

It may be more reasonable to convert just the original referrence

triangle into equivalent equilateral one.

Salute,

Maj. Pestich