www.ConcurrentInverse.com
https://www.cut-the-knot.org/htdocs/dcforum/DCForumID4/606.shtml
There will always be a use for large prime numbers, eg 111, when
expressing approximations to irrational numbers. There are 11*6 feet
in a chain, 13 weeks in a quarter, and 2*11/7 = 3.1428 = Pi + 0.0013.
666 - 720 = 54 = 270/5 deg = 3 Pi / 10 radians
pi/5 is related to the golden ratio
616 - 630 = 14 is not likely to be related to the golden ratio
5**1/2 = 2.2360679774997896964091736687313
(5/7)**1/2 = 0.84515425472851657750961832736595
(5/7)**1/3 = 0.89390353509656765128791642511372
1/ Phi = Phi -1
Phi**2 - Phi -1 = 0
2*Phi = 1 +-(1+4)**0.5 = 1 +- (5)**0.5 = 2* 1.6180339887498948482045868343656
Phi and pentagonal symmetry are discussed in depth at
https://www.mcs.surrey.ac.uk/Personal/r.Knott/Fibonacci/phi2DGeomTrig.html#trigmore
1/(5)**1/2 - 0.44721359549995793928183473374626
pentagonal symmetry pi/5 = 36deg
sin36 = 0.58778525229247312916870595463907
cos36 = 0.80901699437494742410229341718282
= Phi /2 = (1+(5)**0.5)/4
tan36 = 0.72654252800536088589546675748062 = (5-2*5**0.5)**0.5
cos72 = ((5**0.5-1)**0.5/2
Thus in pentagonal symmetry the is a correspondence or relationship of
Phi, 5**0.5 and Pi/5 . Why or how can this be derived?
36-54 triangle hypotenuse = 4
side opposite 36 = 2 Phi = 2.35114100 = 2*1.17557050
side opposite 54 = = 3.236067977
ref: https://www.mcs.surrey.ac.uk/Personal/r.Knott/Fibonacci/simpleTrig.html#xactrig
exact trig values
ref: https://www.mcs.surrey.ac.uk/Personal/r.Knott/Fibonacci/phi2DGeomTrig.html#trigmore
I have observed the phenomenon when I calculated the dodecahedral and
icosahedral angles. Consider a pentagonal jello mold with each if
the five sides a cylinder centered at the center of the pentagon base
with unit vectors going from the center of the pentagon and scribing
an arc to the vertical. At some angle the unit vector points are
unity apart; this defines the dodecahedral symmetry. The sides of
the base are then 2*sin(Pi/5) = 1.176 . If the five unit vectors are
raised by an angle alphathen the sides of the elivated pentagon are
2*cos(alpha)*sin(Pi/5) = 1 .
dodecahedral, icosahedral symmetry
In calculating the unit vectors to the vertices I observed
Phi and/or the square root of 5 cropping up.
cos(pi - dihedral) = 1/5**0.5
We have levels of complexity
Pi/2 2**0.5, Pythagoras, square root
Pi/6 3**0.5
Pi/5 Phi, golden, quadratic equation root
Pi/7 cubic equation root
...
My discussion of possible and impossible things is at
https://www.issi1.com/corwin/possible.txt
ref: https://www.issi1.com/corwin/platonic.txt
https://www.issi1.com/corwin/unit_v.txt
https://www.issi1.com/corwin/vertices.txt
ref: www.vb-helper.com/tutorial_platonic_solids.html
cc:golden numerology
cosmos2000@iquebec.com
www.666myth.co.nr/
cosmos2000@iquebec.com?subject=666 Bivalent Myth
www.chez.com/cosmos2000/Numbers/IsomorphousTriplets.html
www.liftbar.com