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Subject: "URGENT HELP NEEDED for Induction and Divisibility"     Previous Topic | Next Topic
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Becca
guest
Feb-23-06, 07:01 AM (EST)
 
"URGENT HELP NEEDED for Induction and Divisibility"
 
   Use mathematical induction to prove that 5^n + 9^n +2 is divisible by 4 (n belongs to all positive integers).

ok this is what i've got so far:

assume that the statement is true for n=k

let n=k+1

5^(k+1) + 9^(k+1) + 2
(5^k)*5 + (9^k)*9 + 2

and where do i go from here? anyone?


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alexb
Charter Member
1782 posts
Feb-23-06, 09:42 AM (EST)
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1. "RE: URGENT HELP NEEDED for Induction and Divisibility"
In response to message #0
 
   >Use mathematical induction to prove that 5^n + 9^n +2 is
>divisible by 4 (n belongs to all positive integers).
>
>ok this is what i've got so far:
>
>assume that the statement is true for n=k
>
>let n=k+1
>
>5^(k+1) + 9^(k+1) + 2
>(5^k)*5 + (9^k)*9 + 2
>
>and where do i go from here? anyone?

Try subtracting the expression for n = k from the one you just obtained. See what you obtain and do not forget that your assumption that what you subtract is divisible by 4.


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herman hofstede
guest
Feb-24-06, 09:02 AM (EST)
 
2. "RE: URGENT HELP NEEDED for Induction and Divisibility"
In response to message #0
 
   5*5^n+9*9^n+2
= 4*5^n+5^n + 8*9^n+9^n+2
= 4*5^n + 8*9^n + (5^n + 9^n + 2)
= 4*5^n + 4*2*8^n + (5^n + 9^n + 2)
= 4*(5^n + 2*9^n) + (5^n + 9^n +2)
the first term is divisible by 4
the second term is divisible by 4 (induction-step)
so the sum is divisible by 4.
q.e.d.


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