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Subject: "Un-magic square"     Previous Topic | Next Topic
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fleur_ecarlate
Member since Oct-7-05
Oct-07-05, 12:04 PM (EST)
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"Un-magic square"
 
   I have figured how to create a magic square, but is there a way to create un-magic square? In other words, in a 3 by 3 grid place digits 1-9, so that each row, each colomn, each diagonal DO NOT add up to the same number. Thanks!


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alexb
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1670 posts
Oct-07-05, 12:50 PM (EST)
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1. "RE: Un-magic square"
In response to message #0
 
   >I have figured how to create a magic square, but is there a
>way to create un-magic square? In other words, in a 3 by 3
>grid place digits 1-9, so that each row, each colomn, each
>diagonal DO NOT add up to the same number.

You probably mean "all add to a different number," right?

The answer is yes, and probably in many ways. E.g.,

6 7 5
2 8 4
3 9 1

or

2 4 9
5 6 8
7 3 1


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Ramsey2879
guest
Oct-24-05, 05:56 PM (EST)
 
2. "RE: Un-magic square"
In response to message #1
 
   >>I have figured how to create a magic square, but is there a
>>way to create un-magic square? In other words, in a 3 by 3
>>grid place digits 1-9, so that each row, each colomn, each
>>diagonal DO NOT add up to the same number.
>
>You probably mean "all add to a different number," right?
>
>The answer is yes, and probably in many ways. E.g.,
> = 16
>6 7 5 = 17
>2 8 4 = 14
>3 9 1 = 13
>11 10 =15
> 24
>or
> = 22
>2 4 9 = 15
>5 6 8 = 19
>7 3 1 = 11
>14 18 =9
> 11
Maybe we can add a condition that the eight numbers form an a strict numeric sequence, e.g. 11,12,13,14,15,16,17,18 This would mean that the four corners of the square plus 2 times the center square add to 26. If that doesn't work, maybe make the sum of the four corners plus twice the middle square add to 26 plus 8i and begin the eight sequential sums with 11 plus i instead of 11.


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