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Have_Blue
Member since Apr-10-02
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Apr-17-02, 03:33 PM (EST) |
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1. "RE: Question sqrt"
In response to message #0
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Because 7+4*sqrt(3) and 7-4*sqrt(3) are both greater than zero, you can combine both binomials under a single square root operation: sqrt(7+4*sqrt(3))*sqrt(7-4*sqrt(3)) = sqrt((7+4*sqrt(3))*(7-4*sqrt(3))) The expression under the square root symbol is of the form (a+b)*(a-b), where a=7 and b=4*sqrt(3). Multiplying these two binomials gives a^2-b^2. So: = sqrt(7^2-(4sqrt(3))^2) = sqrt(49-16*3) = sqrt(49-48) = sqrt(1) = 1 |
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