AVENEVINS@aol.com" target="_blank">DAVENEVINS@aol.com wrote:
>
> I am not a mathematician but I have
> very much enjoyed reading your manifesto
> on the web. I am trying to learn more about probability.If that's really the case, get yourself a good book on probability and work it out as needed. Visit the site of MAA (https://www.maa.org) and their book store. They must have something popular. I may recommend Balakrishnan's "Combinatorics" which is an outstanding text that in addition to elementary probability covers quite advanced topics.
> I have a quick question that I would
> very much appreciate an answer to.
> Please note the following:
>
> If I have 360 balls in a bag that all
> numbered, obviously the chance of
> picking any one ball is one out of 360.
Yes.
> Now if I have two bags--one with twelve
> balls (let's say with the months of
> the year listed on the balls) and another
> bag with the numbers 1 through 30
> on the balls, what are the odds of me
> picking one particular combination of
> two balls if I get one pick from each
> bag (i.e. what are the chances of
> picking April from one bag and 25 from
> the other bag) --My assumption is that
> the odds are the same 1 out of 360.
> Am I incorrect, and if so kindly advise
> why.
You are right.
Events of extracting a ball from two bags are independent. The probability of two independent events occurring together equals the product of their probabilities. Thus you get 1/12 times 1/30 which is 1/360.
> I very much appreciate your help.
Regards
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