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 Subject: "How to solve a Parabola graphically" Previous Topic | Next Topic
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Jasmine guest
Apr-25-06, 10:02 PM (EST)

"How to solve a Parabola graphically"

mr_homm
Member since May-22-05
Apr-26-06, 08:46 AM (EST)    1. "RE: How to solve a Parabola graphically"
In response to message #0

 Hi Jasmine,>I don't understand how to solve parabola question >grapahically. Can you please help me? What exactly are you trying to do with the parabola? There are lots of different questions you could ask about parabolas, so I need to know which one you are tryng to answer. I'm sure someone here can help you with it, but we need to know exactly what the question is.--Stuart Anderson

PLE guest
Apr-28-06, 09:23 AM (EST)

2. "RE: How to solve a Parabola graphically"
In response to message #0

 To solve a parabola graphically, simply look for the AOS which is x=-b/2a. The x value found using the AOS is the x value for the vertex of the parabola. Now plug this x value into the intial equation which should be set = y. After solving you will have the y value of the Vertex. Now draw a T-chart and put the vertex values in the center of the T chart. Choose other values on each side of the x value found as the vertex and solve y.Now plot the graph. Where ever the parabola crosses the x-axis is the solution to the Quadratic Equation.Remember when solving Quadratic Equations you are looking for all values that would make y=0 therefore that would be any point of the parabola that crosses the x-axis because y=0 along the x-axis. I hope this helped

stapel
Member since Mar-5-02
May-08-06, 01:27 PM (EST)    3. "RE: How to solve a Parabola graphically"
In response to message #0

 >I don't understand how to solve parabola question >grapahically. Can you please help me? To "solve" a quadratic, you find the zeroes. The zeroes are also the x-intercepts (assuming the zeroes are real; that is, that the stuff inside the square root in the Quadratic Formula isn't negative). So "solving" "graphically" means "draw the picture and guess the x-intercepts from the drawing".It isn't the best method for accuracy (what if the x-intercept is at, say, (2/3)sqrt(7)?), but it can be sort-of useful in reinforcing the relationship between "(real) solutions" and "crossing the x-axis".So draw the picture, and guess the x-intercepts from that. (Then check your work -- and fudge the drawing, if necessary -- with the Quadratic Formula.)Eliz.

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