>I don't understand how to solve parabola question
>grapahically. Can you please help me?

What exactly are you trying to do with the parabola? There are lots of different questions you could ask about parabolas, so I need to know which one you are tryng to answer. I'm sure someone here can help you with it, but we need to know exactly what the question is.

--Stuart Anderson

Remember when solving Quadratic Equations you are looking for all values that would make y=0 therefore that would be any point of the parabola that crosses the x-axis because y=0 along the x-axis.

I hope this helped

To "solve" a quadratic, you find the zeroes. The zeroes are also the x-intercepts (assuming the zeroes are real; that is, that the stuff inside the square root in the Quadratic Formula isn't negative). So "solving" "graphically" means "draw the picture and guess the x-intercepts from the drawing".

It isn't the best method for accuracy (what if the x-intercept is at, say, (2/3)sqrt(7)?), but it can be sort-of useful in reinforcing the relationship between "(real) solutions" and "crossing the x-axis".

So draw the picture, and guess the x-intercepts from that. (Then check your work -- and fudge the drawing, if necessary -- with the Quadratic Formula.)

Eliz.