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CTK Exchange
Rakesh MISRA
guest
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Jan-31-08, 11:01 AM (EST) |
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"Mohr-Mascheroni construction: a square from a side"
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Dear Alexander,
I am a mechanical engineer and work as Chief Design Engineer in Indian Railways.
Thank you for a delightful site. It is amazing how you have put together such a lot of math - must have been a lifetime quest! Please accept my especial gratitude for having given a wonderful insight into Mohr-Mascheroni constructions. It is fascinating indeed.
I have two comments to make:
(i) Could you please see problem 4? Perhaps a simpler way exists: raw a semi-circular arc with A as center and AB radius. Then from B, intersect this arc with same AB radius at points X and Y. Then take any radius and draw arcs from X and Y to intersect at C, which is the point such that CAB is a right angle.
(ii) My basic problem is with Problem 9: Building a square with side AB. The solution offered does not appear to work. It is easy to get point C so that CAB is a right angle. But after that, I am not able to proceed with the given solution. You see, the point(s) of intersection of a circle and a line can be found if the center of the circle is NOT ON THE LINE. But, in the current case, it does not appear to be possible to determine the intersection of a semi-circle (with A as center and AB radius) with the line CA. Could you kindly elaborate? Maybe I have not understood the point somewhere.
I eagerly await the opinion of an expert!!With best regards,
Sincerely,
Rakesh MISRA,
INDIA
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alexb
Charter Member
2166 posts |
Jan-31-08, 11:10 AM (EST) |
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2. "RE: Mohr-Mascheroni construction: a square from a side"
In response to message #0
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Thank for being on alert. - You are right in that the radius of the circle can be taken to be AB. I can't explain intelligently why I requested R > AB instead of R ≥ AB. This is an omission that I have corrected.
- Inadvertently I have omitted a reference to problem #7 which is necessary to locate point D. It is now in and the construction appears to go through as intended.
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