p-adic Numbers
The set Qp of p-adic numbers is the completion of the space of all rationals Q when the latter is endowed with a special metric |.|p. Not only Qp is different from R (giving the first example of the dependency of the completion on the underlying metric), but Qp, being defined for every prime p, supplies a sequence of distinct completions of the same set of the rationals.
First, for every prime p, we define norm |.|p, on the set Q of rational numbers. Every nonzero rational number
q = ±pnp1n1p2n2 ·...· pmnm = pn (u / v),
where p and pk are distinct primes and the exponents n and nk may be positive or negative, depending on the prevalence of the power of the corresponsing prime in the numerator or denominator of q; u and v are integers prime to p.
Definition
|q|p = p-n,
where n is the exponent of p in the above factorization. Separately we also define
|1001/1000 - 1|2 = |1/1000|2 = |2-35-3|2 = 8.
Which shows that 1001/1000 and 1 are not at all close in Q2. In Q5, the situation is even worse:
|.|p has three important properties that qualify it as a norm:
1. | |u|p = 0 only if u = 0. | |
2. | |uv|p = |u|p|v|p, for any rational u and v | |
3. | |u + v|p ≤ |u|p + |v|p, for any rational u and v |
In fact the triangle inequality in 3. can be strengthened
3'. | |u + v|p ≤ max{|u|p, |v|p}, for any rational u and v. |
An even stronger result holds:
3''. | For |u|p ≠ |v|p, |u + v|p = max{|u|p, |v|p}, for any rational u and v. |
To prove the latter, assume |u|p < |v|p. Then, by 3',
Norm |.|p is called the p-adic norm (or p-adic absolute value). It was introduced by Kurt Hensel, a student of Leopold Kronecker, in 1902.
The availability of the triangle inequality leads to a definition of a metric
It is easy to give an example of an integer sequence which is Cauchy in the sense of the p-adic norm. The motivation comes from
x0 | = 1, | |
x1 | = 1 + p, | |
x2 | = 1 + p + p², | |
x3 | = 1 + p + p² + p³, | |
... | ||
= 1 + p + p² + ... + pn, | ||
... |
For the sequence {xk}, assuming n > m,
|xn - xm|p | = |pm+1 + ... + pn|p | |
= p-(m+1) |
which tends to 0 as m (and hence n) grows. What p-adic number does {xk} converge to? This is a particular case of what is known as a p-adic expansion.
References
- E. B. Berger, Exploring the Number Jungle, AMS, 2000
- J. R. Goldman, The Queen of Mathematics, A K Peters, 1998
- F. Q. Gouvêa, Local and Global in Number Theory, in The Princeton Companion to Mathematics T. Gowers (ed.), Princeton University Press, 2008
- p-adic Numbers
- p-adic Expansions
- The Local-Global Principle
- Triangulating Squares
- Square Root of 2 is Irrational
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Copyright © 1996-2018 Alexander BogomolnyStrange as it may appear, we'll write
q | = 1 + p + ... + pm + ... |
As we just said, q is well defined as a limit of the sequence {xk} and this is how the identity should be understood. All arithmetic operations are permitted to carry over the limits so that
q | = 1 + p + ... + pm + ... | |
pq | = p + p² + ... + pm+1 + ... | |
= 1 + p + ... + pm + ... = q |
So that pq + 1 = q, implying q = 1 / (1 - p). Taking p = 2 we obtain:
-1 | = 1 + 2 + 4 + ... |
One certainly needs time and effort to get used to such weirdness.
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